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mesak/laravel-api-response

最新稳定版本:v1.3.2

Composer 安装命令:

composer require mesak/laravel-api-response

包简介

build a Laravel api response package

README 文档

README

Laravel Api Response

Control the api format with a unified callback method

installation

composer require mesak/laravel-api-response

Or you could directly reference it into your composer.json file as a dependency

{
  "require": {
    "mesak/laravel-api-response": "^1.0.0"
  }
}

Controller

change your api controller, to extend Mesak\LaravelApiResponse\Http\Controllers\Controller

namespace App\Http\Controllers;

use Mesak\LaravelApiResponse\Http\Controllers\ApiController as BaseController;

class MainController extends BaseController
{

}

then you can return your all response

Example

Use Pagination

class MainController extends BaseController
{

    function index(Request $request)
    {
      return \App\Models\User::paginate(15);
    }
}

Use Resources

class MainController extends BaseController
{

    function index(Request $request)
    {
      $users = \App\Models\User::paginate(15);
      return \App\Http\Resources\User::collection($users);
    }
}

Use Exception

class MainController extends BaseController
{

  function index(Request $request)
  {
    $users = \App\Models\User::paginate(15);
    if( $users->isEmpty() )
    {
      throw new \Exception('No users found');
    }
    return \App\Http\Resources\User::collection($users);
  }
}

Use Extends Exception

class MainController extends BaseController
{
  function index(Request $request)
  {
    $users = \App\Models\User::paginate(15);
    if( $users->isEmpty() )
    {
      throw new \Mesak\LaravelApiResponse\Exceptions\BaseException('No users found' ); //statusCode 500
    }
    return \App\Http\Resources\User::collection($users);
  }
}

Use Custom Exception

create your custom exception class app/Exceptions/BadRequestException.php

namespace App\Exceptions;

class BadRequestException extends \Mesak\LaravelApiResponse\Exceptions\BaseException
{
  protected $errorCode = 400;
  protected $statusCode = 400;
  public function __construct($message = 'Bad Request')
  {
    parent::__construct($message);
  }
}

then you can use it in your controller

use App\Exceptions\BadRequestException;
class MainController extends BaseController
{
  function index(Request $request)
  {
    $users = \App\Models\User::paginate(15);
    if( $users->isEmpty() )
    {
      throw new BadRequestException(); //statusCode 400
    }
    return \App\Http\Resources\User::collection($users);
  }
}

without ApiController

if you don't want to extend Mesak\LaravelApiResponse\Http\Controllers\ApiController you can use

response()->success($data,$statusCode);

response()->error($data,$statusCode);

class MainController extends \App\Http\Controllers\Controller
{
  function index(Request $request)
  {
    $users = \App\Models\User::paginate(15);
    if( $users->isEmpty() )
    {
      return response()->error('no data',400);
    }
    $result = \App\Http\Resources\User::collection($users);
    return response()->success($result);
  }
}

custom config

You can customise your api schema content with a custom config.php.

php artisan vendor:publish --tag=api-response --force

统计信息

  • 总下载量: 45
  • 月度下载量: 0
  • 日度下载量: 0
  • 收藏数: 2
  • 点击次数: 5
  • 依赖项目数: 0
  • 推荐数: 0

GitHub 信息

  • Stars: 2
  • Watchers: 1
  • Forks: 0
  • 开发语言: PHP

其他信息

  • 授权协议: MIT
  • 更新时间: 2022-12-31

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